The solution of the differential equation \[(1+{{x}^{2}})\frac{dy}{dx}=x(1+{{y}^{2}})\]is [AISSE 1983]

\[{{\tan }^{-1}}y=\log (1+{{x}^{2}})+c\]

\[2{{\tan }^{-1}}y=\log (1+{{x}^{2}})+c\]

\[{{\tan }^{-1}}y=\log (1+{{x}^{2}})+c\]

\[2{{\tan }^{-1}}y+\log (1+{{x}^{2}})+c=0\]

The solution of the differential equation \[(1+{{x}^{2}})\frac{dy}{dx}

1.	The solution of the differential equation \[(1+{{x}^{2}})\frac{dy}{dx}=x(1+{{y}^{2}})\]is [AISSE 1983]
A.	\[2{{\tan }^{-1}}y=\log (1+{{x}^{2}})+c\]
B.	\[{{\tan }^{-1}}y=\log (1+{{x}^{2}})+c\]
C.	\[2{{\tan }^{-1}}y+\log (1+{{x}^{2}})+c=0\]
D.	None of these
Answer» B. \[{{\tan }^{-1}}y=\log (1+{{x}^{2}})+c\]

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The solution of the differential equation \[(1+{{x}^{2}})\frac{dy}{dx}=x(1+{{y}^{2}})\]is [AISSE 1983]

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