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The solution of \[\frac{dy}{dx}+y={{e}^{-x}},\,\,y(0)=0\], is [Kerala (Engg.) 2002]

A.                 \[y={{e}^{-x}}(x-1)\]       
B.                 \[y=x{{e}^{x}}\]
C.                 \[y=x{{e}^{-x}}+1\]        
D.                 \[y=x{{e}^{-x}}\]
Answer» E.


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