The solution of \[\frac{dy}{dx}+2y\,\tan x=\sin x\], is [DCE 1999]

\[y\,{{\sec }^{3}}x={{\sec }^{2}}x+c\]

The solution of \[\frac{dy}{dx}+2y\,\tan x=\sin x\], is [DCE 1

1.	The solution of \[\frac{dy}{dx}+2y\,\tan x=\sin x\], is [DCE 1999]
A.	\[y\,{{\sec }^{3}}x={{\sec }^{2}}x+c\]
B.	\[y\,{{\sec }^{2}}x=\sec x+c\]
C.	\[y\,\,\sin x=\tan x+c\]
D.	None of these
Answer» C. \[y\,\,\sin x=\tan x+c\]

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