The solution of \[\frac{{{d}^{2}}y}{d{{x}^{2}}}={{\sec }^{2}}x+x{{e}^{x}}\]is [DSSE 1985]

\[y=\log (\sec x)+(x+2){{e}^{x}}+{{c}_{1}}x+{{c}_{2}}\]

\[y=\log (\sec x)+(x-2){{e}^{x}}+{{c}_{1}}x+{{c}_{2}}\]

\[y=\log (\sec x)-(x+2){{e}^{x}}+{{c}_{1}}x+{{c}_{2}}\]

The solution of \[\frac{{{d}^{2}}y}{d{{x}^{2}}}={{\sec }^{2}}x+x{{e}

1.	The solution of \[\frac{{{d}^{2}}y}{d{{x}^{2}}}={{\sec }^{2}}x+x{{e}^{x}}\]is [DSSE 1985]
A.	\[y=\log (\sec x)+(x-2){{e}^{x}}+{{c}_{1}}x+{{c}_{2}}\]
B.	\[y=\log (\sec x)+(x+2){{e}^{x}}+{{c}_{1}}x+{{c}_{2}}\]
C.	\[y=\log (\sec x)-(x+2){{e}^{x}}+{{c}_{1}}x+{{c}_{2}}\]
D.	None of these
Answer» B. \[y=\log (\sec x)+(x+2){{e}^{x}}+{{c}_{1}}x+{{c}_{2}}\]

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The solution of \[\frac{{{d}^{2}}y}{d{{x}^{2}}}={{\sec }^{2}}x+x{{e}^{x}}\]is [DSSE 1985]

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