MCQOPTIONS
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| 1. |
The solution of \[\frac{{{d}^{2}}y}{d{{x}^{2}}}=\cos x-\sin x\]is |
| A. | \[y=-\cos x+\sin x+{{c}_{1}}x+{{c}_{2}}\] |
| B. | \[y=-\cos x-\sin x+{{c}_{1}}x+{{c}_{2}}\] |
| C. | \[y=\cos x-\sin x+{{c}_{1}}{{x}^{2}}+{{c}_{2}}x\] |
| D. | \[y=\cos x+\sin x+{{c}_{1}}{{x}^{2}}+{{c}_{2}}x\] |
| Answer» B. \[y=-\cos x-\sin x+{{c}_{1}}x+{{c}_{2}}\] | |