1.

The solution of \[\frac{{{d}^{2}}y}{d{{x}^{2}}}=\cos x-\sin x\]is

A. \[y=-\cos x+\sin x+{{c}_{1}}x+{{c}_{2}}\]                  
B. \[y=-\cos x-\sin x+{{c}_{1}}x+{{c}_{2}}\]                          
C. \[y=\cos x-\sin x+{{c}_{1}}{{x}^{2}}+{{c}_{2}}x\]       
D. \[y=\cos x+\sin x+{{c}_{1}}{{x}^{2}}+{{c}_{2}}x\]
Answer» B. \[y=-\cos x-\sin x+{{c}_{1}}x+{{c}_{2}}\]                          


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