1.

The solubility product of \[AgCl\] is \[4.0\times {{10}^{-10}}\] at \[298\,\,K.\] The solubility of \[AgCl\]in \[0.04\,m\,\,CaC{{l}_{2}}\] will be [KCET 1996]

A.        \[2.0\times {{10}^{-5}}\,m\]       
B.        \[1.0\times {{10}^{-4}}\,m\]
C.        \[5.0\times {{10}^{-9}}\,m\]       
D.        \[2.2\times {{10}^{-4}}\,m\]
Answer» D.        \[2.2\times {{10}^{-4}}\,m\]


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