The smallest interval \[[a,\,\,b]\] such that \[\int_{0}^{1}{\frac{dx}{\sqrt{1+{{x}^{4}}}}}\in [a,\,\,b]\] is given by

\[\left[ \frac{1}{\sqrt{2}},\,\,1 \right]\]

\[\left[ \frac{1}{2},\,\,2 \right]\]

\[\left[ \frac{3}{4},\,\,1 \right]\]

The smallest interval \[[a,\,\,b]\] such that \[\int_{0}^{1}{\frac{dx}

1.	The smallest interval \[[a,\,\,b]\] such that \[\int_{0}^{1}{\frac{dx}{\sqrt{1+{{x}^{4}}}}}\in [a,\,\,b]\] is given by
A.	\[\left[ \frac{1}{\sqrt{2}},\,\,1 \right]\]
B.	\[[0,\,\,1]\]
C.	\[\left[ \frac{1}{2},\,\,2 \right]\]
D.	\[\left[ \frac{3}{4},\,\,1 \right]\]
Answer» B. \[[0,\,\,1]\]

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The smallest interval \[[a,\,\,b]\] such that \[\int_{0}^{1}{\frac{dx}{\sqrt{1+{{x}^{4}}}}}\in [a,\,\,b]\] is given by

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