MCQOPTIONS
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| 1. |
The slope of the tangent at \[(x,y)\]to a curve passing through \[\left( 1,\frac{\pi }{4} \right)\]is given by \[\frac{y}{x}-{{\cos }^{2}}\left( \frac{y}{x} \right)\], then the equation of the curve is [Kurukshetra CEE 2002] |
| A. | \[y={{\tan }^{-1}}\left[ \log \left( \frac{e}{x} \right) \right]\] |
| B. | \[y=x{{\tan }^{-1}}\left[ \log \left( \frac{x}{e} \right) \right]\] |
| C. | \[y=x{{\tan }^{-1}}\left[ \log \left( \frac{e}{x} \right) \right]\] |
| D. | None of these |
| Answer» D. None of these | |