The slope of the tangent at (x, y) to a curve passing through \[\left( 1,\frac{\pi }{4} \right)\] is given by \[\frac{y}{x}-{{\cos }^{2}}\left( \frac{y}{x} \right)\] , then the equation of

\[y={{\tan }^{-1}}\left( \log \left( \frac{e}{x} \right) \right)\]

\[y=x{{\tan }^{-1}}\left( \log \left( \frac{x}{e} \right) \right)\]

\[y=x{{\tan }^{-1}}\left( \log \left( \frac{e}{x} \right) \right)\]

The slope of the tangent at (x, y) to a curve passing through \[\left(

1.	The slope of the tangent at (x, y) to a curve passing through \[\left( 1,\frac{\pi }{4} \right)\] is given by \[\frac{y}{x}-{{\cos }^{2}}\left( \frac{y}{x} \right)\] , then the equation of
A.	\[y={{\tan }^{-1}}\left( \log \left( \frac{e}{x} \right) \right)\]
B.	\[y=x{{\tan }^{-1}}\left( \log \left( \frac{x}{e} \right) \right)\]
C.	\[y=x{{\tan }^{-1}}\left( \log \left( \frac{e}{x} \right) \right)\]
D.	None of thee
Answer» D. None of thee

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The slope of the tangent at (x, y) to a curve passing through \[\left( 1,\frac{\pi }{4} \right)\] is given by \[\frac{y}{x}-{{\cos }^{2}}\left( \frac{y}{x} \right)\] , then the equation of

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