%_The simple pitot tube does not measure the_%

1.	%_The simple pitot tube does not measure the_%
A.	Static pressure
B.	Dynamic pressure
C.	Velocity at the stagnation point
D.	All of the above
Answer» E.

Discussion

No Comment Found

Related MCQs

A centrifugal pump is used to pump water through a horizontal distance of 150 m, and then raised to an overhead tank 10 m above. The pipe is smooth with an I.D of 50 mm. What head (m of water) must the pump generate at its exit (E) to deliver water at a flow rate of 0.001 m/s? The Fanning friction factor, is 0.0062.
Hydraulic mean depth () for a circular pipe of diameter 'D' flowing full is 0.25 D. For a circular channel, at = 0.3 D, gives the condition for the maximum
The terminal velocity of a particle moving through a fluid varies as d. What is the value of n' for Newton's law regime ?
A Bingham fluid of viscosity μ = 10 Pa.s and yield stress, τ = 10 KPa, is shared between flat parallel plates separated by a distance of 10 m. The top plate is moving with a velocity of 1 m/s. The shear stress on the plate is
For Laminar flow through a packed bed, the pressure drop is proportional to ( is the superficial liquid velocity and is the particle diameter)
Dimension of surface tension is(where, = force, = length)
Co-efficient of discharge () is defined as actual discharge/theoretical discharge and is equal to . ; where = Co-efficient of contraction and = co-efficient of velocity. of an orifice is usually about
The drag co-efficient for a bacterium moving in water at 1 mm/s, will be of the following order of magnitude (assume size of the bacterium to be 1 micron and kinematic viscosity of water to be 10m/s).
For the free settling of a spherical particle through a fluid, the slope of, C-log N , plot is
Buckingham-π theorem states that in any physical problem including '' quantities having '' diamensions, the quantities can be arranged into __________ independent dimensionless parameters.

%_The simple pitot tube does not measure the_%

Discussion

No Comment Found

Related MCQs

Reply to Comment