The shortest distance between the lines \[\frac{x-3}{3}=\frac{y-8}{-1}=\frac{z-3}{1}\] and \[\frac{x+3}{-3}=\frac{y+7}{2}=\frac{z-6}{4}\] is [RPET 2001; MP PET 2002]

The shortest distance between the lines \[\frac{x-3}{3}=\frac{y-8}{-1}

1.	The shortest distance between the lines \[\frac{x-3}{3}=\frac{y-8}{-1}=\frac{z-3}{1}\] and \[\frac{x+3}{-3}=\frac{y+7}{2}=\frac{z-6}{4}\] is [RPET 2001; MP PET 2002]
A.	\[\sqrt{30}\]
B.	\[2\sqrt{30}\]
C.	\[5\sqrt{30}\]
D.	\[3\sqrt{30}\]
Answer» E.

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The shortest distance between the lines \[\frac{x-3}{3}=\frac{y-8}{-1}=\frac{z-3}{1}\] and \[\frac{x+3}{-3}=\frac{y+7}{2}=\frac{z-6}{4}\] is [RPET 2001; MP PET 2002]

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