The rusting of iron takes place as follows 2H+ + 2e- + ½O2 \[\xrightarrow{{}}\] H2O(l) ; E° = +1.23 V Fe2+ + 2e- \[\xrightarrow{{}}\] Fe(s) ; E° = -0.44 V Calculate DG° for the net process [IIT 2005]

The rusting of iron takes place as follows �

1.	The rusting of iron takes place as follows 2H+ + 2e- + ½O2 \[\xrightarrow{{}}\] H2O(l) ; E° = +1.23 V Fe2+ + 2e- \[\xrightarrow{{}}\] Fe(s) ; E° = -0.44 V Calculate DG° for the net process [IIT 2005]
A.	-322 kJ mol-1
B.	-161 kJ mol-1
C.	-152 kJ mol-1
D.	-76 kJ mol-1
Answer» B. -161 kJ mol-1

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The rusting of iron takes place as follows 2H+ + 2e- + ½O2 \[\xrightarrow{{}}\] H2O(l) ; E° = +1.23 V Fe2+ + 2e- \[\xrightarrow{{}}\] Fe(s) ; E° = -0.44 V Calculate DG° for the net process [IIT 2005]

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