The roots of the equation\[({{a}^{2}}+{{b}^{2}}){{t}^{2}}-2(ac+bd)t+({{c}^{2}}+{{d}^{2}})=0\] are equal, then [MP PET 1996]

The roots of the equation\[({{a}^{2}}+{{b}^{2}}){{t}^{2}}-2(ac+bd)t+({

1.	The roots of the equation\[({{a}^{2}}+{{b}^{2}}){{t}^{2}}-2(ac+bd)t+({{c}^{2}}+{{d}^{2}})=0\] are equal, then [MP PET 1996]
A.	\[ab=dc\]
B.	\[ac=bd\]
C.	\[ad+bc=0\]
D.	\[\frac{a}{b}=\frac{c}{d}\]
Answer» E.

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The roots of the equation\[({{a}^{2}}+{{b}^{2}}){{t}^{2}}-2(ac+bd)t+({{c}^{2}}+{{d}^{2}})=0\] are equal, then [MP PET 1996]

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