1.

The roots of the equation \[{{x}^{2}}+ax+b=0\]are p,  and q, then the equation whose roots are \[{{p}^{2}}q\] and \[p{{q}^{2}}\] will be [MP PET 1980]

A. \[{{x}^{2}}+abx+{{b}^{3}}=0\]
B. \[{{x}^{2}}-abx+{{b}^{3}}=0\]
C. \[b{{x}^{2}}+x+a=0\]
D. \[{{x}^{2}}+ax+ab=0\]
Answer» B. \[{{x}^{2}}-abx+{{b}^{3}}=0\]


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