1.

The relationship between K‘eq and ∆G‘° is$

A. ∆G<sup>‘°</sup> = RTlnK<sup>‘</sup><sub>eq</sub>
B. ∆G<sup>‘°</sup> = -RTK<sup>‘</sup><sub>eq</sub>
C. ∆G<sup>‘°</sup> = RK<sup>‘</sup><sub>eq</sub>
D. ∆G<sup>‘°</sup> = -RK<sup>‘</sup><sub>eq</sub>
Answer» C. ‚Äö√Ñ√∂‚àö‚Ć‚àö√∫G<sup>‚Äö√Ñ√∂‚àö√ë‚àö‚⧬¨¬®‚Äö√†√ª</sup> = RK<sup>‚Äö√Ñ√∂‚àö√ë‚àö‚â§</sup><sub>eq</sub>


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