The ratio of electrostatic and gravitational forces acting between electron and proton separated by a distance $$5\times {{10}^{-11}}m,$$ will be (Charge on electron $$=\text{ 1}.\text{6}\times \text{1}{{0}^{\text{19}}}C$$, mass of electron $$=\text{ 9}.\text{1}\times \text{1}{{0}^{\text{31}}}kg$$, mass of proton = $$1.6\times {{10}^{-27}}kg,$$ $$\,G=6.7\times {{10}^{-11}}\,N{{m}^{2}}/k{{g}^{2}})$$ [RPET 1997; Pb PMT 2003]

Question

The ratio of electrostatic and gravitational forces acting between electron and proton separated by a distance $$5\times {{10}^{-11}}m,$$ will be (Charge on electron $$=\text{ 1}.\text{6}\times \text{1}{{0}^{\text{19}}}C$$, mass of electron $$=\text{ 9}.\text{1}\times \text{1}{{0}^{\text{31}}}kg$$, mass of proton = $$1.6\times {{10}^{-27}}kg,$$ $$\,G=6.7\times {{10}^{-11}}\,N{{m}^{2}}/k{{g}^{2}})$$                  [RPET 1997; Pb PMT 2003]

TuteeHUB · Accepted Answer

$$\text{2}.\text{36}\times \text{1}{{0}^{40}}$$

TuteeHUB · Answer

$$\text{2}.\text{36}\times \text{1}{{0}^{\text{39}}}$$

TuteeHUB · Answer

$$\text{2}.\text{34}\times \text{1}{{0}^{41}}$$

TuteeHUB · Answer

$$\text{2}.\text{34}\times \text{1}{{0}^{42}}$$

1.	The ratio of electrostatic and gravitational forces acting between electron and proton separated by a distance \[5\times {{10}^{-11}}m,\] will be (Charge on electron \[=\text{ 1}.\text{6}\times \text{1}{{0}^{\text{19}}}C\], mass of electron \[=\text{ 9}.\text{1}\times \text{1}{{0}^{\text{31}}}kg\], mass of proton = \[1.6\times {{10}^{-27}}kg,\] \[\,G=6.7\times {{10}^{-11}}\,N{{m}^{2}}/k{{g}^{2}})\] [RPET 1997; Pb PMT 2003]
A.	\[\text{2}.\text{36}\times \text{1}{{0}^{\text{39}}}\]
B.	\[\text{2}.\text{36}\times \text{1}{{0}^{40}}\]
C.	\[\text{2}.\text{34}\times \text{1}{{0}^{41}}\]
D.	\[\text{2}.\text{34}\times \text{1}{{0}^{42}}\]
Answer» B. \[\text{2}.\text{36}\times \text{1}{{0}^{40}}\]

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