MCQOPTIONS
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| 1. |
The rate law for a reaction between the substances A and B is given by, rate \[=k{{[A]}^{n}}{{[B]}^{m}}\]. On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as [AIEEE 2003] |
| A. | \[\frac{1}{{{2}^{(m+n)}}}\] |
| B. | \[(m+n)\] |
| C. | \[(n-m)\] |
| D. | \[{{2}^{(n-m)}}\] |
| Answer» E. | |