The range of \[f(x)=co{{s}^{-1}}\left( \frac{1+{{x}^{2}}}{2x} \right)+\sqrt{2-{{x}^{2}}}\]is

\[\left\{ 1,\,\,1+\pi \right\}\]

\[\left\{ 0,\,\,1+\frac{\pi }{2} \right\}\]

\[\left\{ 0,\,\,1+\pi \right\}\]

\[\left\{ 1,\,\,1+\frac{\pi }{2} \right\}\]

The range of \[f(x)=co{{s}^{-1}}\left( \frac{1+{{x}^{2}}}{2x} \right)+

1.	The range of \[f(x)=co{{s}^{-1}}\left( \frac{1+{{x}^{2}}}{2x} \right)+\sqrt{2-{{x}^{2}}}\]is
A.	\[\left\{ 0,\,\,1+\frac{\pi }{2} \right\}\]
B.	\[\left\{ 0,\,\,1+\pi \right\}\]
C.	\[\left\{ 1,\,\,1+\frac{\pi }{2} \right\}\]
D.	\[\left\{ 1,\,\,1+\pi \right\}\]
Answer» D. \[\left\{ 1,\,\,1+\pi \right\}\]

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The range of \[f(x)=co{{s}^{-1}}\left( \frac{1+{{x}^{2}}}{2x} \right)+\sqrt{2-{{x}^{2}}}\]is

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