The probability that the birth days of six different persons will fall in exactly two calendar months is

\[^{12}{{C}_{2}}\times \frac{{{2}^{6}}}{{{12}^{6}}}\]

\[^{12}{{C}_{2}}\times \frac{{{2}^{6}}-1}{{{12}^{6}}}\]

The probability that the birth days of six different persons will fall

1.	The probability that the birth days of six different persons will fall in exactly two calendar months is
A.	\[\frac{1}{6}\]
B.	\[^{12}{{C}_{2}}\times \frac{{{2}^{6}}}{{{12}^{6}}}\]
C.	\[^{12}{{C}_{2}}\times \frac{{{2}^{6}}-1}{{{12}^{6}}}\]
D.	\[\frac{341}{{{12}^{5}}}\]
Answer» E.

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The probability that the birth days of six different persons will fall in exactly two calendar months is

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