The probability of choosing at random a number that is divisible by 6 or 8 from among 1 to 90 is equal to [Pb. CET 2002]

The probability of choosing at random a number that is divisible by 6

1.	The probability of choosing at random a number that is divisible by 6 or 8 from among 1 to 90 is equal to [Pb. CET 2002]
A.	\[\frac{1}{6}\]
B.	\[\frac{1}{30}\]
C.	\[\frac{11}{80}\]
D.	\[\frac{23}{90}\]
Answer» E.

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The probability of choosing at random a number that is divisible by 6 or 8 from among 1 to 90 is equal to [Pb. CET 2002]

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