The price of an articles was increased by r%. Later the new price was decreased by r%. If the latest price was Rs. 1, then the original price was :

s. $$\left( {\frac{{1 - {r^2}}}{{100}}} \right)$$

s. $$\frac{{\sqrt {1 - {r^2}} }}{{100}}$$

s. $$\frac{{10000}}{{\left( {10000 - {r^2}} \right)}}$$

The price of an articles was increased by r%. Later the new price was

1.	The price of an articles was increased by r%. Later the new price was decreased by r%. If the latest price was Rs. 1, then the original price was :
A.	s. 1
B.	s. $$\left( {\frac{{1 - {r^2}}}{{100}}} \right)$$
C.	s. $$\frac{{\sqrt {1 - {r^2}} }}{{100}}$$
D.	s. $$\frac{{10000}}{{\left( {10000 - {r^2}} \right)}}$$
Answer» E.

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The price of an articles was increased by r%. Later the new price was decreased by r%. If the latest price was Rs. 1, then the original price was :

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