The potential energy of a particle of mass m is given by \[U(x)=\left\{ \begin{matrix} {{E}_{0}}; \\ 0; \\ \end{matrix}\begin{matrix} 0\le x\le 1 \\ x>1 \\ \end{matrix} \right.\] \[{{\lambda }_{1}}\] and \[{{\lambda }_{2}}\] are the de Broglie wavelengths of the particle, when \[0\le x\le 1\]and \[x>1\] respectively. If the total energy of particle is 2\[{{E}_{0}}\], the ratio \[\frac{{{\lambda }_{0}}}{{{\lambda }_{2}}}\] will be

The potential energy of a particle of mass m is given by \[U(x)=\left\

1.	The potential energy of a particle of mass m is given by \[U(x)=\left\{ \begin{matrix} {{E}_{0}}; \\ 0; \\ \end{matrix}\begin{matrix} 0\le x\le 1 \\ x>1 \\ \end{matrix} \right.\] \[{{\lambda }_{1}}\] and \[{{\lambda }_{2}}\] are the de Broglie wavelengths of the particle, when \[0\le x\le 1\]and \[x>1\] respectively. If the total energy of particle is 2\[{{E}_{0}}\], the ratio \[\frac{{{\lambda }_{0}}}{{{\lambda }_{2}}}\] will be
A.	2
B.	1
C.	\[\sqrt{2}\]
D.	\[\frac{1}{\sqrt{2}}\]
Answer» D. \[\frac{1}{\sqrt{2}}\]