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1. |
The potential difference applied to an X-ray tube is 5kV and the current through it is 3.2 mA. Then the number of electrons striking the target per second is [IIT-JEE (Screening) 2002] |
A. | \[2\times {{10}^{16}}\] |
B. | \[5\times {{10}^{16}}\] |
C. | \[1\times {{10}^{17}}\] |
D. | \[4\times {{10}^{15}}\] |
Answer» B. \[5\times {{10}^{16}}\] | |