The position of a projectile launched from the origin at \[t=0\]is given by \[\vec{r}=(40\hat{i}+50\hat{j})m\] at 2s. If the projectile was launched at an angle \[\theta \] from the horizontal, then \[\theta \] is (take \[\text{g = 10 m}{{\text{s}}^{-2}}\])

• A. \[{{\tan }^{-1}}\frac{2}{3}\]   
• B.        \[{{\tan }^{-1}}\frac{3}{2}\]
• C. \[{{\tan }^{-1}}\frac{7}{4}\]   
• D.        \[{{\tan }^{-1}}\frac{4}{5}\]