1.

The points D, E, F divide BC, CA and AB of the triangle ABC in the ratio 1 : 4, 3 : 2 and 3 : 7 respectively and the point K divides AB in the ratio \[1:3\], then \[(\overrightarrow{AD}+\overrightarrow{BE}+\overrightarrow{CF})\,\,:\,\,\overrightarrow{CK}\] is equal to [MNR 1987]

A. 1 : 1                                          
B. 0.0868055555555556
C. 5 : 2                                          
D. None of these
Answer» C. 5 : 2                                          


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