MCQOPTIONS
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| 1. |
The points D, E, F divide BC, CA and AB of the triangle ABC in the ratio 1 : 4, 3 : 2 and 3 : 7 respectively and the point K divides AB in the ratio \[1:3\], then \[(\overrightarrow{AD}+\overrightarrow{BE}+\overrightarrow{CF})\,\,:\,\,\overrightarrow{CK}\] is equal to [MNR 1987] |
| A. | 1 : 1 |
| B. | 0.0868055555555556 |
| C. | 5 : 2 |
| D. | None of these |
| Answer» C. 5 : 2 | |