The point where the line \[\frac{x-1}{2}=\frac{y-2}{-3}=\frac{z+3}{4}\] meets the plane \[2x+4y-z=1\], is [DSSE 1981]

The point where the line \[\frac{x-1}{2}=\frac{y-2}{-3}=\frac{z+3}{4}\

1.	The point where the line \[\frac{x-1}{2}=\frac{y-2}{-3}=\frac{z+3}{4}\] meets the plane \[2x+4y-z=1\], is [DSSE 1981]
A.	(3, ?1, 1)
B.	(3, 1, 1)
C.	(1, 1, 3)
D.	(1, 3, 1)
Answer» B. (3, 1, 1)

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The point where the line \[\frac{x-1}{2}=\frac{y-2}{-3}=\frac{z+3}{4}\] meets the plane \[2x+4y-z=1\], is [DSSE 1981]

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