The point at which the tangent to the curve \[y=2{{x}^{2}}-x+1\] is parallel to \[y\text{ }=\text{ 3}x+\text{9 }\]will be [Karnataka CET 2001]

The point at which the tangent to the curve \[y=2{{x}^{2}}-x+1\] is pa

1.	The point at which the tangent to the curve \[y=2{{x}^{2}}-x+1\] is parallel to \[y\text{ }=\text{ 3}x+\text{9 }\]will be [Karnataka CET 2001]
A.	(2, 1)
B.	(1, 2)
C.	(3, 9)
D.	(?2, 1)
Answer» C. (3, 9)

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The point at which the tangent to the curve \[y=2{{x}^{2}}-x+1\] is parallel to \[y\text{ }=\text{ 3}x+\text{9 }\]will be [Karnataka CET 2001]

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