The plane \[lx+my=0\] is rotated an angle \[\alpha \] about its line of intersection with the plane \[z=0\], then the equation to the plane in its new position is

\[lx-my\pm z\sqrt{({{l}^{2}}+{{m}^{2}})}\tan \alpha =0\]

\[lx+my\pm z\sqrt{({{l}^{2}}+{{m}^{2}})}\tan \alpha =0\]

\[lx+my\pm z\sqrt{({{l}^{2}}+{{m}^{2}})}\cos \alpha =0\]

\[lx-my\pm z\sqrt{({{l}^{2}}+{{m}^{2}})}\cos \alpha =0\]

The plane \[lx+my=0\] is rotated an angle \[\alpha \] about its line o

1.	The plane \[lx+my=0\] is rotated an angle \[\alpha \] about its line of intersection with the plane \[z=0\], then the equation to the plane in its new position is
A.	\[lx+my\pm z\sqrt{({{l}^{2}}+{{m}^{2}})}\tan \alpha =0\]
B.	\[lx-my\pm z\sqrt{({{l}^{2}}+{{m}^{2}})}\tan \alpha =0\]
C.	\[lx+my\pm z\sqrt{({{l}^{2}}+{{m}^{2}})}\cos \alpha =0\]
D.	\[lx-my\pm z\sqrt{({{l}^{2}}+{{m}^{2}})}\cos \alpha =0\]
Answer» B. \[lx-my\pm z\sqrt{({{l}^{2}}+{{m}^{2}})}\tan \alpha =0\]

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The plane \[lx+my=0\] is rotated an angle \[\alpha \] about its line of intersection with the plane \[z=0\], then the equation to the plane in its new position is

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