The photoelectric threshold wavelength of silver is $$3250\times {{10}^{-10}}m.$$The velocity of the electron ejected from a silver surface by ultraviolet light of wavelength $$2536\times {{10}^{-10\,}}$$m is (Given$$h=4.14\times {{10}^{-15}}eV\text{ and }c=3\times {{10}^{8}}m{{s}^{-1}}$$)

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TuteeHUB · Accepted Answer

$$=61\times {{10}^{3}}m{{s}^{-1}}$$

TuteeHUB · Answer

$$=0.6\times {{10}^{6}}m{{s}^{-1}}$$

TuteeHUB · Answer

$$=0.3\times {{10}^{6}}m{{s}^{-1}}$$

TuteeHUB · Answer

$$=6\times {{10}^{6}}m{{s}^{-1}}$$

1.	The photoelectric threshold wavelength of silver is \[3250\times {{10}^{-10}}m.\]The velocity of the electron ejected from a silver surface by ultraviolet light of wavelength \[2536\times {{10}^{-10\,}}\]m is (Given\[h=4.14\times {{10}^{-15}}eV\text{ and }c=3\times {{10}^{8}}m{{s}^{-1}}\])
A.	\[=0.6\times {{10}^{6}}m{{s}^{-1}}\]
B.	\[=61\times {{10}^{3}}m{{s}^{-1}}\]
C.	\[=0.3\times {{10}^{6}}m{{s}^{-1}}\]
D.	\[=6\times {{10}^{6}}m{{s}^{-1}}\]
Answer» B. \[=61\times {{10}^{3}}m{{s}^{-1}}\]

The photoelectric threshold wavelength of silver is \[3250\times {{10}^{-10}}m.\]The velocity of the electron ejected from a silver surface by ultraviolet light of wavelength \[2536\times {{10}^{-10\,}}\]m is (Given\[h=4.14\times {{10}^{-15}}eV\text{ and }c=3\times {{10}^{8}}m{{s}^{-1}}\])

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