1.

The  phase  difference  between  two  waves  represented  by \[{{y}_{1}}={{10}^{-6}}\sin [100\,t+(x/50)+0.5]m\]            \[{{y}_{2}}={{10}^{-6}}\cos \,[100\,t+(x/50)]m\] where x is expressed in metres and t is expressed in seconds, is approximately                 [CBSE PMT 2004]

A.            1.5 rad                                    
B.            1.07 rad
C.            2.07 rad                                  
D.            0.5 rad
Answer» C.            2.07 rad                                  


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