MCQOPTIONS
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| 1. |
The phase difference between two waves represented by \[{{y}_{1}}={{10}^{-6}}\sin [100\,t+(x/50)+0.5]m\] \[{{y}_{2}}={{10}^{-6}}\cos \,[100\,t+(x/50)]m\] where x is expressed in metres and t is expressed in seconds, is approximately [CBSE PMT 2004] |
| A. | 1.5 rad |
| B. | 1.07 rad |
| C. | 2.07 rad |
| D. | 0.5 rad |
| Answer» C. 2.07 rad | |