The path difference between the two waves \[{{y}_{1}}={{a}_{1}}\sin \,\left( \omega t-\frac{2\pi x}{\lambda } \right)\] and \[{{y}_{2}}={{a}_{2}}\cos \,\left( \omega t-\frac{2\pi x}{\lambda }+\varphi \right)\] is [MP PMT 1994]

\[\frac{2\pi }{\lambda }\left( \varphi -\frac{\pi }{2} \right)\]

\[\frac{\lambda }{2\pi }\varphi \]

\[\frac{\lambda }{2\pi }\left( \varphi +\frac{\pi }{2} \right)\]

\[\frac{2\pi }{\lambda }\varphi \]

The path difference between the two waves \[{{y}_{1}}={{a}_{1}}\sin \,

1.	The path difference between the two waves \[{{y}_{1}}={{a}_{1}}\sin \,\left( \omega t-\frac{2\pi x}{\lambda } \right)\] and \[{{y}_{2}}={{a}_{2}}\cos \,\left( \omega t-\frac{2\pi x}{\lambda }+\varphi \right)\] is [MP PMT 1994]
A.	\[\frac{\lambda }{2\pi }\varphi \]
B.	\[\frac{\lambda }{2\pi }\left( \varphi +\frac{\pi }{2} \right)\]
C.	\[\frac{2\pi }{\lambda }\left( \varphi -\frac{\pi }{2} \right)\]
D.	\[\frac{2\pi }{\lambda }\varphi \]
Answer» C. \[\frac{2\pi }{\lambda }\left( \varphi -\frac{\pi }{2} \right)\]