MCQOPTIONS
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| 1. |
The P.E. of a particle executing SHM at a distance x from its equilibrium position is [Roorkee 1992; CPMT 1997; RPMT 1999] |
| A. | \[\frac{1}{2}m{{\omega }^{2}}{{x}^{2}}\] |
| B. | \[\frac{1}{2}m{{\omega }^{2}}{{a}^{2}}\] |
| C. | \[\frac{1}{2}m{{\omega }^{2}}({{a}^{2}}-{{x}^{2}})\] |
| D. | Zero |
| Answer» B. \[\frac{1}{2}m{{\omega }^{2}}{{a}^{2}}\] | |