The ordinates of the triangle inscribed in parabola \[{{y}^{2}}=4ax\] are \[{{y}_{1}},\ {{y}_{2}},\ {{y}_{3}}\], then the area of triangle is

\[\frac{1}{8a}({{y}_{1}}-{{y}_{2}})({{y}_{2}}-{{y}_{3}})({{y}_{3}}-{{y}_{1}})\]

\[\frac{1}{8a}({{y}_{1}}+{{y}_{2}})({{y}_{2}}+{{y}_{3}})({{y}_{3}}+{{y}_{1}})\]

\[\frac{1}{4a}({{y}_{1}}+{{y}_{2}})({{y}_{2}}+{{y}_{3}})({{y}_{3}}+{{y}_{1}})\]

\[\frac{1}{4a}({{y}_{1}}-{{y}_{2}})({{y}_{2}}-{{y}_{3}})({{y}_{3}}-{{y}_{1}})\]

The ordinates of the triangle inscribed in parabola \[{{y}^{2}}=4ax\]

1.	The ordinates of the triangle inscribed in parabola \[{{y}^{2}}=4ax\] are \[{{y}_{1}},\ {{y}_{2}},\ {{y}_{3}}\], then the area of triangle is
A.	\[\frac{1}{8a}({{y}_{1}}+{{y}_{2}})({{y}_{2}}+{{y}_{3}})({{y}_{3}}+{{y}_{1}})\]
B.	\[\frac{1}{4a}({{y}_{1}}+{{y}_{2}})({{y}_{2}}+{{y}_{3}})({{y}_{3}}+{{y}_{1}})\]
C.	\[\frac{1}{8a}({{y}_{1}}-{{y}_{2}})({{y}_{2}}-{{y}_{3}})({{y}_{3}}-{{y}_{1}})\]
D.	\[\frac{1}{4a}({{y}_{1}}-{{y}_{2}})({{y}_{2}}-{{y}_{3}})({{y}_{3}}-{{y}_{1}})\]
Answer» C. \[\frac{1}{8a}({{y}_{1}}-{{y}_{2}})({{y}_{2}}-{{y}_{3}})({{y}_{3}}-{{y}_{1}})\]

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The ordinates of the triangle inscribed in parabola \[{{y}^{2}}=4ax\] are \[{{y}_{1}},\ {{y}_{2}},\ {{y}_{3}}\], then the area of triangle is

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