MCQOPTIONS
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| 1. |
The orbital speed of electron orbiting around a nucleus in a circular orbit of radius 50 pm is\[2.2\times {{10}^{6}}\,m{{s}^{-1}}\]. Then the magnetic dipole moment of an electron is |
| A. | \[1.6\times {{10}^{-19}}A{{m}^{2}}\] |
| B. | \[5.3\times {{10}^{-21}}A{{m}^{2}}\] |
| C. | \[8.8\times {{10}^{-26}}A{{m}^{2}}\] |
| D. | \[8.8\times {{10}^{-25}}A{{m}^{2}}\] |
| Answer» D. \[8.8\times {{10}^{-25}}A{{m}^{2}}\] | |