The orbital angular momentum for an electron revolving in an orbit is given by \[\sqrt{l(l+1)}\frac{h}{2\pi }\]. This momentum for \[{{d}^{5}},\,{{d}^{6}},\,{{p}^{3}}\] electron will be respectively

\[\sqrt{6}\,\frac{h}{2\pi },\,\sqrt{6}\frac{h}{2\pi },\,\sqrt{3}\frac{h}{2\pi }\]

\[\sqrt{6}\,\frac{h}{2\pi },\,\sqrt{7}\,\frac{h}{2\pi },\,\sqrt{2}\,\frac{h}{2\pi }\]

\[0\,\frac{\sqrt{6}h}{2\pi },\,\frac{\sqrt{2}h}{2\pi }\]

\[\sqrt{6}\,\frac{h}{2\pi },\,\sqrt{6}\frac{6}{2\pi },\,\sqrt{2}\frac{h}{2\pi }\]

The orbital angular momentum for an electron revolving in an orbit is

1.	The orbital angular momentum for an electron revolving in an orbit is given by \[\sqrt{l(l+1)}\frac{h}{2\pi }\]. This momentum for \[{{d}^{5}},\,{{d}^{6}},\,{{p}^{3}}\] electron will be respectively
A.	\[\sqrt{6}\,\frac{h}{2\pi },\,\sqrt{7}\,\frac{h}{2\pi },\,\sqrt{2}\,\frac{h}{2\pi }\]
B.	\[0\,\frac{\sqrt{6}h}{2\pi },\,\frac{\sqrt{2}h}{2\pi }\]
C.	\[\sqrt{6}\,\frac{h}{2\pi },\,\sqrt{6}\frac{6}{2\pi },\,\sqrt{2}\frac{h}{2\pi }\]
D.	\[\sqrt{6}\,\frac{h}{2\pi },\,\sqrt{6}\frac{h}{2\pi },\,\sqrt{3}\frac{h}{2\pi }\]
Answer» D. \[\sqrt{6}\,\frac{h}{2\pi },\,\sqrt{6}\frac{h}{2\pi },\,\sqrt{3}\frac{h}{2\pi }\]

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The orbital angular momentum for an electron revolving in an orbit is given by \[\sqrt{l(l+1)}\frac{h}{2\pi }\]. This momentum for \[{{d}^{5}},\,{{d}^{6}},\,{{p}^{3}}\] electron will be respectively

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