1.

The number of ways to give 16 different things to three persons A,B,C so that B gets one more than A and C gets two more than B is

A. \[\frac{16!}{4!5!7!}\]    
B. \[4!5!7!\]
C. \[\frac{16!}{3!5!8!}\]    
D. none of these
Answer» B. \[4!5!7!\]


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