The number of real solutions of the equation\[\sqrt{1+\cos 2x}=\sqrt{2}{{\sin }^{-1}}(sinx),-\pi \le x\le \pi \] is

The number of real solutions of the equation\[\sqrt{1+\cos 2x}=\sqrt{2

1.	The number of real solutions of the equation\[\sqrt{1+\cos 2x}=\sqrt{2}{{\sin }^{-1}}(sinx),-\pi \le x\le \pi \] is
A.	0
B.	1
C.	2
D.	infinite
Answer» D. infinite

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The number of real solutions of the equation\[\sqrt{1+\cos 2x}=\sqrt{2}{{\sin }^{-1}}(sinx),-\pi \le x\le \pi \] is

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