MCQOPTIONS
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| 1. |
The number of atoms in 100 g of an fcc crystal with density, \[d=10g/c{{m}^{3}}\] and cell edge equal to 100 pm, is equal to |
| A. | \[1\times {{10}^{25}}\] |
| B. | \[2\times {{10}^{25}}\] |
| C. | \[3\times {{10}^{25}}\] |
| D. | \[4\times {{10}^{25}}\] |
| Answer» E. | |