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1. |
The number of atoms in 100 g of an fcc crystal with density, \[d=10g/c{{m}^{3}}\] and cell edge equal to 100 pm, is equal to |
A. | \[1\times {{10}^{25}}\] |
B. | \[2\times {{10}^{25}}\] |
C. | \[3\times {{10}^{25}}\] |
D. | \[4\times {{10}^{25}}\] |
Answer» E. | |