MCQOPTIONS
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| 1. |
The nth derivative of x2y2 + (1-x2)y1 + xy = 0 is, |
| A. | x<sup>2</sup>y<sub>n+2</sub> + y<sub>n</sub>(2n<sup>2</sup>-2n-2nx+x) – y<sub>n-1</sub>(2n<sup>2</sup>-3n)=0 |
| B. | x<sup>2</sup>y<sub>n+2</sub> + y<sub>n+1</sub>(2nx-x<sup>2</sup>) + y<sub>n</sub>(2n<sup>2</sup>-2n-2nx+x) – y<sub>n-1</sub>(2n<sup>2</sup>-3n)=0 |
| C. | x<sup>2</sup>y<sub>n+2</sub> + y<sub>n+1</sub>(2nx+1-x<sup>2</sup>) + y<sub>n</sub>(2n<sup>2</sup>-2n-2nx+x)-y<sub>n – 1</sub>(2n<sup>2</sup>-3n)=0 |
| D. | x<sup>2</sup>y<sub>n+2</sub> + y<sub>n+1</sub>(2nx+1-x<sup>2</sup>) + xy<sub>n</sub>2n<sup>2</sup>-y<sub>n – 1</sub>(2n<sup>2</sup>-3n)=0 |
| Answer» D. x<sup>2</sup>y<sub>n+2</sub> + y<sub>n+1</sub>(2nx+1-x<sup>2</sup>) + xy<sub>n</sub>2n<sup>2</sup>-y<sub>n ‚Äö√Ñ√∂‚àö√ë‚àö¬® 1</sub>(2n<sup>2</sup>-3n)=0 | |