1.

The net heat exchange between the two grey surfaces may be written as

A. (Q <sub>12</sub>) <sub>NET </sub>= E <sub>b 1 </sub>– E <sub>b 2</sub>/ (1 – e <sub>1</sub>/A <sub>1</sub> e<sub> 1</sub> + 1/A <sub>1 </sub>F <sub>12</sub> + 1 – e <sub>2</sub>/A <sub>2</sub> e<sub> 2</sub>)
B. (Q <sub>12</sub>) <sub>NET </sub>= 2 E <sub>b 1 </sub>– E <sub>b 2</sub>/ (1 – e <sub>1</sub>/A <sub>1</sub> e<sub> 1</sub> + 1/A <sub>1 </sub>F <sub>12</sub> + 1 – e <sub>2</sub>/A <sub>2</sub> e<sub> 2</sub>)
C. (Q <sub>12</sub>) <sub>NET </sub>= E <sub>b 1 </sub>– 2 E <sub>b 2</sub>/ (1 – e <sub>1</sub>/A <sub>1</sub> e<sub> 1</sub> + 1/A <sub>1 </sub>F <sub>12</sub> + 1 – e <sub>2</sub>/A <sub>2</sub> e<sub> 2</sub>)
D. (Q <sub>12</sub>) <sub>NET </sub>= 2 E <sub>b 1 </sub>– 3 E <sub>b 2</sub>/ (1 – e <sub>1</sub>/A <sub>1</sub> e<sub> 1</sub> + 1/A <sub>1 </sub>F <sub>12</sub> + 1 – e <sub>2</sub>/A <sub>2</sub> e<sub> 2</sub>)
Answer» B. (Q <sub>12</sub>) <sub>NET </sub>= 2 E <sub>b 1 </sub>‚Äö√Ñ√∂‚àö√ë‚àö¬® E <sub>b 2</sub>/ (1 ‚Äö√Ñ√∂‚àö√ë‚àö¬® e <sub>1</sub>/A <sub>1</sub> e<sub> 1</sub> + 1/A <sub>1 </sub>F <sub>12</sub> + 1 ‚Äö√Ñ√∂‚àö√ë‚àö¬® e <sub>2</sub>/A <sub>2</sub> e<sub> 2</sub>)


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