The molar freezing point constant for water is \[{{1.86}^{o}}C\,mol{{e}^{-1}}\]. If 342 gm of canesugar \[({{C}_{12}}{{H}_{22}}{{O}_{11}})\] are dissolved in 1000 \[gm\] of water, the solution will freeze at [NCERT 1977; CPMT 1989; Roorkee 2000; DCE 2004]

The molar freezing point constant for water is \[{{1.86}^{o}}C\,mol{{e

1.	The molar freezing point constant for water is \[{{1.86}^{o}}C\,mol{{e}^{-1}}\]. If 342 gm of canesugar \[({{C}_{12}}{{H}_{22}}{{O}_{11}})\] are dissolved in 1000 \[gm\] of water, the solution will freeze at [NCERT 1977; CPMT 1989; Roorkee 2000; DCE 2004]
A.	\[-{{1.86}^{o}}C\]
B.	\[{{1.86}^{o}}C\]
C.	\[-{{3.92}^{o}}C\]
D.	\[{{2.42}^{o}}C\]
Answer» B. \[{{1.86}^{o}}C\]

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The molar freezing point constant for water is \[{{1.86}^{o}}C\,mol{{e}^{-1}}\]. If 342 gm of canesugar \[({{C}_{12}}{{H}_{22}}{{O}_{11}})\] are dissolved in 1000 \[gm\] of water, the solution will freeze at [NCERT 1977; CPMT 1989; Roorkee 2000; DCE 2004]

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