The minimum value of function \[f(x)=3{{x}^{4}}-8{{x}^{3}}+12{{x}^{2}}-48x+25\] on [0, 3] is equal to [Pb. CET 2004]

The minimum value of function \[f(x)=3{{x}^{4}}-8{{x}^{3}}+12{{x}^{2}}

1.	The minimum value of function \[f(x)=3{{x}^{4}}-8{{x}^{3}}+12{{x}^{2}}-48x+25\] on [0, 3] is equal to [Pb. CET 2004]
A.	25
B.	? 39
C.	? 25
D.	39
Answer» C. ? 25

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The minimum value of function \[f(x)=3{{x}^{4}}-8{{x}^{3}}+12{{x}^{2}}-48x+25\] on [0, 3] is equal to [Pb. CET 2004]

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