MCQOPTIONS
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| 1. |
The mean free path of electrons in a metal is \[4\times {{10}^{-8}}\,m\]. The electric field which can give on an average 2 eV energy to an electron in the metal will be in unit of \[V{{m}^{-1}}\] [AIPMT (S) 2009] |
| A. | \[8\times {{10}^{7}}\] |
| B. | \[5\times {{10}^{-11}}\] |
| C. | \[8\times {{10}^{-11}}\] |
| D. | \[5\times {{10}^{7}}\] |
| Answer» E. | |