The maximum value of \[f(x)=\frac{x}{4+x+{{x}^{2}}}\] on \[[-1,\,1]\] is [MP PET 2000]

The maximum value of \[f(x)=\frac{x}{4+x+{{x}^{2}}}\] on \[[-1,\,1]\]

1.	The maximum value of \[f(x)=\frac{x}{4+x+{{x}^{2}}}\] on \[[-1,\,1]\] is [MP PET 2000]
A.	\[-1/4\]
B.	\[-1/3\]
C.	\[1/6\]
D.	\[1/5\]
Answer» D. \[1/5\]

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The maximum value of \[f(x)=\frac{x}{4+x+{{x}^{2}}}\] on \[[-1,\,1]\] is [MP PET 2000]

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