The maximum height is reached in 5 seconds by a stone thrown vertically upwards and moving under the equation 10s = 10ut ? 49\[{{t}^{2}}\], where s is in metre and t is in second. The value of u is

The maximum height is reached in 5 seconds by a stone thrown verticall

1.	The maximum height is reached in 5 seconds by a stone thrown vertically upwards and moving under the equation 10s = 10ut ? 49\[{{t}^{2}}\], where s is in metre and t is in second. The value of u is
A.	\[4.9m/\sec \]
B.	\[49m/\sec \]
C.	\[98m/\sec \]
D.	None of these
Answer» C. \[98m/\sec \]

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The maximum height is reached in 5 seconds by a stone thrown vertically upwards and moving under the equation 10s = 10ut ? 49\[{{t}^{2}}\], where s is in metre and t is in second. The value of u is

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