MCQOPTIONS
Saved Bookmarks
| 1. |
The magnetic field at O due to current in the infinite wire forming a loop as shown in Fig. is |
| A. | \[\frac{{{\mu }_{0}}I}{2\pi d}(\cos {{\phi }_{1}}+\cos {{\phi }_{2}})\] |
| B. | \[\frac{{{\mu }_{0}}I2I}{4\pi d}(tan{{\theta }_{1}}+\tan {{\theta }_{2}})\] |
| C. | \[\frac{{{\mu }_{0}}I}{4\pi d}(sin{{\phi }_{1}}+\sin {{\phi }_{2}})\] |
| D. | \[\frac{{{\mu }_{0}}I}{4\pi d}(cos{{\theta }_{1}}+\sin {{\theta }_{2}})\] |
| Answer» B. \[\frac{{{\mu }_{0}}I2I}{4\pi d}(tan{{\theta }_{1}}+\tan {{\theta }_{2}})\] | |