1.

The logarithmic mean temperature difference (tm) is given by (where Δt1 and Δt2 are temperature differences between the hot and cold fluids at entrance and exit)

A. tm = (Δt1 - Δt2)/ loge (Δt1/Δt2)
B. tm = loge (Δt1/Δt2)/ (Δt1 - Δt2)
C. tm = (Δt1 - Δt1) loge(Δt1/Δt1)
D. tm = loge (Δt1 - Δt2)/ Δt1/Δt2
Answer» B. tm = loge (Δt1/Δt2)/ (Δt1 - Δt2)


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