MCQOPTIONS
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| 1. |
The locus of the point of intersection of two tangents of the ellipse \[\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{2}}}{{{b}^{2}}}=1\] which are inclined at angles \[{{\theta }_{1}}\], and \[{{\theta }_{2}}\] with the major axis such that \[{{\tan }^{2}}{{\theta }_{1}}+{{\tan }^{2}}{{\theta }_{2}}\] is constant, is |
| A. | \[4{{x}^{2}}{{y}^{2}}+2({{x}^{2}}-{{a}^{2}})({{y}^{2}}-{{b}^{2}})=k{{({{x}^{2}}-{{a}^{2}})}^{2}}\] |
| B. | \[4{{x}^{2}}{{y}^{2}}-2({{x}^{2}}-{{a}^{2}})({{y}^{2}}-{{b}^{2}})=k{{({{x}^{2}}-{{a}^{2}})}^{2}}\] |
| C. | \[4{{x}^{2}}{{y}^{2}}-2({{x}^{2}}-{{a}^{2}})({{y}^{2}}-{{b}^{2}})=k{{({{x}^{2}}+{{a}^{2}})}^{2}}\] |
| D. | None of these |
| Answer» C. \[4{{x}^{2}}{{y}^{2}}-2({{x}^{2}}-{{a}^{2}})({{y}^{2}}-{{b}^{2}})=k{{({{x}^{2}}+{{a}^{2}})}^{2}}\] | |