The locus of the point of intersection of perpendicular tangents to the ellipse \[\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{2}}}{{{b}^{2}}}=1\], is [MP PET 1995]

\[{{x}^{2}}-{{y}^{2}}={{a}^{2}}+{{b}^{2}}\]

\[{{x}^{2}}+{{y}^{2}}={{a}^{2}}-{{b}^{2}}\]

\[{{x}^{2}}-{{y}^{2}}={{a}^{2}}-{{b}^{2}}\]

\[{{x}^{2}}+{{y}^{2}}={{a}^{2}}+{{b}^{2}}\]

The locus of the point of intersection of perpendicular tangents to th

1.	The locus of the point of intersection of perpendicular tangents to the ellipse \[\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{2}}}{{{b}^{2}}}=1\], is [MP PET 1995]
A.	\[{{x}^{2}}+{{y}^{2}}={{a}^{2}}-{{b}^{2}}\]
B.	\[{{x}^{2}}-{{y}^{2}}={{a}^{2}}-{{b}^{2}}\]
C.	\[{{x}^{2}}+{{y}^{2}}={{a}^{2}}+{{b}^{2}}\]
D.	\[{{x}^{2}}-{{y}^{2}}={{a}^{2}}+{{b}^{2}}\]
Answer» D. \[{{x}^{2}}-{{y}^{2}}={{a}^{2}}+{{b}^{2}}\]

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The locus of the point of intersection of perpendicular tangents to the ellipse \[\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{2}}}{{{b}^{2}}}=1\], is [MP PET 1995]

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